From b30d708daa8c59b5af600417eb7b6859c003244a Mon Sep 17 00:00:00 2001
From: Christoph Lehmann <christoph.lehmann@ufz.de>
Date: Wed, 12 Sep 2018 17:20:42 +0200
Subject: [PATCH] [web] md -> pandoc

---
 .../{hertz-contact.md => hertz-contact.pandoc}              | 6 +++---
 1 file changed, 3 insertions(+), 3 deletions(-)
 rename web/content/docs/benchmarks/python-bc/hertz-contact/{hertz-contact.md => hertz-contact.pandoc} (93%)

diff --git a/web/content/docs/benchmarks/python-bc/hertz-contact/hertz-contact.md b/web/content/docs/benchmarks/python-bc/hertz-contact/hertz-contact.pandoc
similarity index 93%
rename from web/content/docs/benchmarks/python-bc/hertz-contact/hertz-contact.md
rename to web/content/docs/benchmarks/python-bc/hertz-contact/hertz-contact.pandoc
index c249033c430..57af17b0ac0 100644
--- a/web/content/docs/benchmarks/python-bc/hertz-contact/hertz-contact.md
+++ b/web/content/docs/benchmarks/python-bc/hertz-contact/hertz-contact.pandoc
@@ -25,7 +25,7 @@ The aim of this test is:
 ## Problem description
 
 Two elastic spheres of same radius $R$ are brought into contact.
-The sphere centers are displaced towards each other by $w\_0$, with increasing
+The sphere centers are displaced towards each other by $w_0$, with increasing
 values in every load step.
 Due to symmetry reasons a flat circular contact area of radius $a$ forms.
 
@@ -35,7 +35,7 @@ The contact between the two spheres is modelled as a Dirichlet BC
 on a varying boundary. The exact boundary and Dirichlet values for the
 $y$ displacements are determined in a Python script.
 Compared to the sketch above the prescribed $y$ displacements correspond
-to $w\_0/2$, because due to symmetry only half of the system (a section of the
+to $w_0/2$, because due to symmetry only half of the system (a section of the
 lower sphere) is simulated.
 
 
@@ -47,7 +47,7 @@ in [this book (in German)](http://www.uni-magdeburg.de/ifme/l-festigkeit/pdf/Ber
 The radius of the contact area is given by
 $$
 \begin{equation}
-a = \sqrt{\frac{w\_0 R}{2}}
+a = \sqrt{\frac{w_0 R}{2}}
 \end{equation}
 $$
 
-- 
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